12=0.019s^2

Solution for 12=0.019s^2 equation:

12=0.019s^2

We move all terms to the left:

12-(0.019s^2)=0

We get rid of parentheses

-0.019s^2+12=0

a = -0.019; b = 0; c = +12;
Δ = b2-4ac
Δ = 02-4·(-0.019)·12
Δ = 0.912
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.912}}{2*-0.019}=\frac{0-\sqrt{0.912}}{-0.038}
=-\frac{\sqrt{}}{-0.038}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.912}}{2*-0.019}=\frac{0+\sqrt{0.912}}{-0.038}
=\frac{\sqrt{}}{-0.038}
$